This question was previously asked in

DSSSB PGT Hindi Female General Section - 3 July 2021 Shift 3

Option 1 : 6

Given:

The first largest four digit number is divisible by 11

And the second largest four digit number is divisible by 16

Concept used:

Simply applying division and subtraction concept

Calculations:

We know that

The largest 4 - digit number is 9999

For the first case which is divisible by 11

⇒ 9999/11 = 99 and reminder is equal to 0

So, the first four digit largest number is 9999

Similarly,

For the second case which is divisible by 16

⇒ 9999/16 = 624 and reminder is 15

Hence, the second four digit largest number is (9999 - 15) = 9984

Then, Difference is

⇒ (9 + 9 + 9 + 9) - (9 + 9 + 8 + 4)

⇒ (36 - 30) = 6

∴ Correct option is (1)